3/(p-2)^2-5/(p-2)+4

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Solution for 3/(p-2)^2-5/(p-2)+4 equation: 


D( p )

p-2 = 0

(p-2)^2 = 0

p-2 = 0

p-2 = 0

p-2 = 0 // + 2

p = 2

(p-2)^2 = 0

(p-2)^2 = 0

p-2 = 0 // + 2

p = 2

p in (-oo:2) U (2:+oo)

3/((p-2)^2)-(5/(p-2))+4 = 0

3/((p-2)^2)-5*(p-2)^-1+4 = 0

3/((p-2)^2)-5/(p-2)+4 = 0

3/((p-2)^2)+(-5*(p-2))/((p-2)^2)+(4*(p-2)^2)/((p-2)^2) = 0

4*(p-2)^2-5*(p-2)+3 = 0

4*p^2-5*p-16*p+13+16 = 0

4*p^2-21*p+29 = 0

4*p^2-21*p+29 = 0

4*p^2-21*p+29 = 0

DELTA = (-21)^2-(4*4*29)

DELTA = -23

DELTA < 0

1 = 0

1/((p-2)^2) = 0

1/((p-2)^2) = 0 // * (p-2)^2

1 = 0

p belongs to the empty set

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